F(x)=2x^2-12x+22

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Solution for F(x)=2x^2-12x+22 equation: 



(F)=2F^2-12F+22

We move all terms to the left:

(F)-(2F^2-12F+22)=0

We get rid of parentheses

-2F^2+F+12F-22=0

We add all the numbers together, and all the variables

-2F^2+13F-22=0

a = -2; b = 13; c = -22;
Δ = b2-4ac
Δ = 132-4·(-2)·(-22)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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